Step 1 : Create a database table

Step 2 : Click on visual studio create a new project

Step 3 : Connect your database

Step 4 : Create a new class 

 public class ImageViewModel
    {
        public int ImageId { get; set; }
        public string ImageTitle { get; set; }
        public byte[] ImageByte { get; set; }
        public string ImagePath { get; set; }
        public HttpPostedFileWrapper ImageFile { get; set; }
    }

Step 5 : Create a controller and write this below code.

public class HomeController : Controller
    {
        public ActionResult Index()
        {
            MVCTutorialEntities db = new MVCTutorialEntities();
            return View();
        }

        public JsonResult ImageUpload(ImageViewModel model)
        {
            MVCTutorialEntities db = new MVCTutorialEntities();
            int imgId = 0;
            var file = model.ImageFile;
            byte[] imagebyte = null;
            if (file != null)
            {
                file.SaveAs(Server.MapPath("/UploadImage/"+file.FileName));
                BinaryReader reader = new BinaryReader(file.InputStream);
                imagebyte = reader.ReadBytes(file.ContentLength);
                StoreImage img = new StoreImage();
                img.ImageTitle = file.FileName;
                img.ImageByte = imagebyte;
                img.ImagePath = "/UploadImage/" + file.FileName;
                db.StoreImages.Add(img);
                db.SaveChanges();
                imgId = img.ImageId;
            }
            return Json(imgId, JsonRequestBehavior.AllowGet);
        }

        public ActionResult DisplayingImage(int imgid)
        {
            MVCTutorialEntities db = new MVCTutorialEntities();

            var img = db.StoreImages.SingleOrDefault(x => x.ImageId == imgid);
            return File(img.ImageByte, "image/jpg");
        }

Step 6: Create a view and write this below code.

@model UploadImageInDataBase.Models.ImageViewModel

<br /><br />

<div class="container">
    <div class="col-md-4">
        <input type="file" id="SelectImage" /><br />
        <a href="#" class="btn btn-sm btn-danger" onclick="UploadImage()">Upload</a>
    </div>

    <div class="col-md-4 thumbnail" id="UploadedImage"></div>
</div>
<script src="~/Scripts/jquery-1.10.2.min.js"></script>

<script>
    var UploadImage = function () {
        var file = $("#SelectImage").get(0).files;
        var data = new FormData;
        data.append("ImageFile", file[0]);
        $.ajax({
            type: "POST",
            url: "/Home/ImageUpload",
            data: data,
            contentType: false,
            processData: false,
            success: function (imgID) {
                $("#UploadedImage").append('<img src="/Home/DisplayingImage?imgID=' + imgID + '"class=img-responsive  thimbnail"/>');
            }
        })
    }

</script>

 Now run this application